Problem 6

Problem: 

The sum of the squares of the first ten natural numbers is,

12 + 22 + … + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + … + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.


My Solution:

n=100
sumOfSquares = 0
for i in range(1,n+1):
sumOfSquares += i**2

squareOfSums = (n*(n+1)/2)**2

print squareOfSums - sumOfSquares